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Maths Help - The Student Room 11 Sep 2022 · y = ax^n taking logs of both sides: logy = loga + nlogx y = kb^x taking logs of both sides: logy = logk + xlogb So, when plotting, you will always have the variable that contains x …
Logarithms and non-linear data help - The Student Room I was attempting this question to do with logarithms and non-linear data, the question is as follows: 1.) The data below follows a trend of the form y=ax^n x 3 5 8 10 15 y 16.3 33.3 64.3 …
Maths help - The Student Room 19 May 2020 · For theoretical purposes, y=kb^x will probably be steeper than y=ax^n, provided b>1. If b<1, y=kb^x will get very flat very quickly.
y= ax^n graph and y=kb^x graph - The Student Room 2 Apr 2020 · I think that the only easy way to do it is to plot both log (y) against x (in which case use y=ab x) and log (y) against log (x) (in which case use y=ax n). But it is very unlikely you …
Year 2 Stats A Level Maths Question - The Student Room 20 Mar 2024 · After applying logs to both sides of P=ab^T I got logP= loga + Tlogb. In terms of comparing coefficients, I guess logb is the gradient and loga is the y-intercept? After assuming …
Logarithmic Graphs - y=ax^n - The Student Room 3 Jun 2024 · You will get a straight line of the form y=mx+c y = mx +c, since you are plotting on a graph with axes \log (x) log(x) and \log (y) log(y). Comparing coefficients with y=mx+c y = mx …
Help with Logs! - The Student Room The variables x and y are connected by a relationship of the form y=ax^n, where a and n are constants.
Reduction of Equations of the form y=ax^ (n) to linear form? 4 Jun 2024 · Determine the law connecting Q and H, showing on your graph the point of interception and the gradient.) Ok so I understand so far that I have to use the laws of logs to …
Young's double slit formula - The Student Room 17 Jun 2024 · For the formula lambda = (ax)/D, I want to know does x represents the distance from the central fringe to the first fringe (taking it as an example) or would it be the distance …
Log graphs - The Student Room 6 Nov 2021 · The graph is drawn to represent the equation y = Axn, where A and n are constant. (b) Hence find the value of A and of n. where do I start? part a asked for the equation of the …