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If tan (x) =5/12, then what is sin x and cos x? - Socratic 15 Apr 2015 · Viewed as a right angled triangle tan(x)=5/12 can be thought of as the ratio of opposite to adjacent sides in a triangle with sides 5, 12 and 13 (where 13 is derived from the …
Find the derivative of tan x using first principle of derivatives - Toppr Find the derivative of tan √ x w.r.t x, using first principle. View Solution. Q5.
Special Limits Involving sin(x), x, and tan(x) - Calculus | Socratic For very small values of x, the functions \sin(x), x, and \tan(x) are all approximately equal. This can be found by using the Squeeze Law.
How do you find the Maclaurin Series for tan x? | Socratic 16 May 2018 · How do you find the Maclaurin Series for #tan x#? Calculus Power Series Constructing a Maclaurin Series. 1 ...
How do you prove #1+tan^2 (x) = sec^2 (x)#? - Socratic 1 Oct 2016 · See explanation... Starting from: cos^2(x) + sin^2(x) = 1 Divide both sides by cos^2(x) to get: cos^2(x)/cos^2(x) + sin^2(x)/cos^2(x) = 1/cos^2(x) which simplifies to: 1+tan^2(x) = …
What is the derivative of #y=tan(x)# - Socratic 18 Aug 2014 · The derivative of tanx is sec^2x. To see why, you'll need to know a few results. First, you need to know that the derivative of sinx is cosx. Here's a proof of that result from first …
How do you simplify the expression 1+tan^2x? | Socratic 19 Oct 2016 · Change to sines and cosines then simplify. #1+tan^2x=1+(sin^2x)/cos^2x# #=(cos^2x+sin^2x)/cos^2x# but #cos^2x+sin^2x=1#
How do you find the derivative of y=tan(x) using first ... - Socratic 6 Jul 2018 · By Definition, # d/dx[f(x)]=lim_(t to x) {f(t)-f(x)}/(t-x)#. #:. d/dx[tanx]=lim_(t to x) (tant-tanx)/(t-x)#, ...
What is the taylor series expansion for the tangent function (tanx ... 22 May 2018 · tan x = x + 1/3x^3 +2/15x^5 + ... The Maclaurin series is given by f(x) = f(0) + (f'(0))/(1!)x + (f''(0))/(2!)x^2 + (f'''(0))/(3!)x^3 + ... (f^((n))(0))/(n!)x^n ...
How do you find the integral of int tan^n (x) if n is an integer ... 28 Sep 2015 · See the explanation section below. For n >= 3, use Integration by substitution to decrease the exponent on tanx int tan^nx dx = int tan^(n-2) tan^2x dx = int tan^(n-2) (sec^2x - …