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Find square root of 3969 by prime factorization - Brainly.in 11 Aug 2018 · Answer: Required square root is 63. Step-by-step explanation: Given number is 3969 Here we want to find square root of the given digit. By prime factorisation, first we need …
Find √3969 by thelong division method - Brainly.in 4 Nov 2022 · Given: the given value is 3969 required: find the square root by long division method explanation: so, the square root of 3969 is 63 final answer: th final answer is 63
If the square root of 3,969 = 63, then find the values of the 24 Jul 2021 · If the square root of 3,969 = 63, then find the values of the following: (a) 0.003969 Full answer plz
Square root long division 3969 - Brainly.in 4 Nov 2022 · Now we add 6+6 =12 and write in the place of divisor then we find a number such that 12n multipwhich is less than or equal 369. We find the number 3 that is 123 multiply 3 is …
Show that each of the following numbers is a perfect square Show that each of the following numbers is a perfect square. Also, find the square root of each : (iv) 3969 (… Get the answers you need, now!
How to find square root of 3969 - Brainly.in 9 Mar 2021 · 3969 =3 × 3 × 3 × 3 × 7 × 7 Here After pairing the same prime factors, no factor is left. Therefore, 3969 is a perfect square of 3 × 3 × 7 = 63.
Square root of 3969 by long division method - Brainly.in Square root of 3969 by long division method Get the answers you need, now!
3. Find the square root using long division method: 3969 2601 Click here 👆 to get an answer to your question ️ 3. Find the square root using long division method: 3969 2601 .
find the square root of 3969 by division method and then use 20 Jun 2019 · find the square root of 3969 by division method and then use it to find the value of square root 39.6 9 + square root 0.39 69 - 10654584
Find the square root of 3969 by the division method - Brainly Answer: There are the following steps to obtain the value of 3969−−−−√ using a long division method. (a) Write the number 3969 as 39¯¯¯¯¯69¯¯¯¯¯ . (b). Find the number whose square …