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Note: Conversion is based on the latest values and formulas.
What is the square root of negative 8? - Socratic 18 Mar 2018 · #sqrt(8)# can be rewritten as: #sqrt(4 * 2 * -1)# We can use this rule for radicals to simplify the ...
How do you simplify #8/sqrt(8)#? - Socratic 14 May 2015 · Both the numerator and denominator of a fraction can be multiplied by the same real number (not equal to zero), without changing the value of a fraction.
How do you simplify 2 sqrt 8 - Socratic 3 Mar 2018 · 2 sqrt(8) - 2 sqrt(2) = 2 sqrt(4*2) - 2 sqrt(2) =4 sqrt(2) - 2sqrt(2) =2 sqrt(2) First rewrite the radical on the left using this rule for radicals:
How do you simplify #sqrt(18/8)#? - Socratic 5 Oct 2016 · Algebra Radicals and Geometry Connections Multiplication and Division of Radicals. 1 Answer . Alan P
What is #sqrt(8)+sqrt(18)-sqrt(32)#? - Socratic The numbers 8, 18, and 32 are perfect squares multiplied by 2. sqrt8+sqrt18-sqrt32 Split up the invidual square roots, (sqrt4xxsqrt2)+(sqrt9xxsqrt2)+(sqrt16xxsqrt2) Square root the perfect squares, 2sqrt2+3sqrt2+4sqrt2 Add them all up, 9sqrt2 Done :D
How do you simplify radical 8? - Socratic 3 Apr 2018 · sqrt(8) = sqrt(4)sqrt(2) = 2sqrt(2) When simplifying radical expressions, one should try to factor each radicand into a product of perfect squares.
What is the square root of 8 to the nearest integer? - Socratic 22 Apr 2018 · sqrt(8) ~~ 3 Note that: 2^2 = 4 < 8 < 9 = 3^2 Hence the (positive) square root of 8 is somewhere between 2 and 3. Since 8 is much closer to 9 = 3^2 than 4 = 2^2, we can deduce that the closest integer to the square root is 3. We can use this proximity of the square root of 8 to 3 to derive an efficient method for finding approximations. Consider a quadratic with zeros …
How do you simplify #sqrt(2) / sqrt(8)#? - Socratic 2 May 2016 · How do you simplify #sqrt(2) / sqrt(8)#? Algebra Radicals and Geometry Connections Multiplication and Division of Radicals. 1 Answer
How do you simplify square root of 8 + square root of 32? 9 Sep 2015 · #sqrt(8) = sqrt(2^2xx2) = sqrt(2^2)*sqrt(2) = 2sqrt(2)# #sqrt(32) = sqrt(4^2xx2) =sqrt(4^2)*sqrt(2) = 4sqrt(2)#
What is the irrational conjugate of - Socratic 15 Aug 2016 · 1-sqrt 8 and 1-sqrt(-8)=1-i sqrt 8, where i symbolizes sqrt(-1). The conjugate of the irrational number in the form a+bsqrt c, where c is positive and a, b and c are rational (including computer string-approximations to irrational and transcendental numbers) is a-bsqrt c' When c is negative, the number is termed complex and the conjugate is a+ibsqrt(|c|), where i = sqrt(-1). …