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Estimate \\sqrt{16.1} using the linearization L(x) of f(x) = \\sqrt{x ... Find the linearization of the function f ( x ) = \sqrt { x + 8 } at a=1 and use it to approximate the numbers \sqrt { 8.97 } and \sqrt { 9.03 }. Are these approximations overestimates or underestimate
How do you simplify #sqrt(16-x^2)#? - Socratic 27 Jul 2015 · You cannot really simplify this, but you way want to rewrite. Since 16-x^2=(4-x)(4+x) you can write: =sqrt((4-x)(4+x)) or: =sqrt(4-x)*sqrt(4+x) This will only work if -4<=x<=+4, otherwise 16-x^2 will be negative = not allowed.
How do you simplify #sqrt (16) / (sqrt (4) + sqrt (2))#? - Socratic 26 Jun 2016 · Let's start with the original: #sqrt16/(sqrt4+sqrt2)# Let's first take the square roots of the perfect squares: ...
What is sqrt(-16), written in the form a+bi? - Socratic 21 Jan 2016 · 0+4i sqrt(-16 =sqrt((-1)(16))=sqrt(-1)sqrt(16)=i4=0+4i implies sqrt(-16)=0+4i
How do you solve sqrt(4x +16) = x +1? - Socratic How do you solve #sqrt(4x +16) = x +1#? Algebra Radicals and Geometry Connections Radical Equations. 1 ...
Use differentials to approximate \sqrt{16.2} using the value of the ... Estimate \sqrt{16.1} using the linearization L(x) of f(x) = \sqrt{x} at a = 16. Also, find the actual value of \sqrt{16.1} (Round your answer to three decimal places.) Use differentials to approximate the value of \sqrt{4.3}. Estimate 1/ \sqrt{14.4} using …
How do you simplify #sqrt(16)#? - Socratic 13 Jul 2015 · sqrt(16) = 4 sqrt(a) = b means that b is a non-negative value (a restriction on the square root symbol ...
Simplify the number using the imaginary unit i. \sqrt{-16} Express \sqrt{-27} in terms of the imaginary number __i__. Simplify. (4 square root of 10)/(square root of 5) Simplify by rationalizing the denominator. 4(sqrt)6/(sqrt)30; Simplify by rationalizing the denominator (5 - sqrt(7)) / (9 - sqrt(14)) Simplify by rationalizing the denominator: dfrac{18}{sqrt{6; Simplify the expression. square root 36 ...
What is the square root of 16.2? - Socratic 9 Sep 2015 · sqrt(16.2) = (9sqrt(5))/5 ~~ 4.0249 Use: sqrt(ab) = sqrt(a)sqrt(b) if a, b >= 0 and: sqrt(a^2) = a if a >= 0 sqrt(16.2) = sqrt(81/5) = sqrt((9^2*5)/(5^2)) = sqrt(9^2/ ...
What is the square root of (16/25)? - Socratic 5 Sep 2015 · So #sqrt(16/25) = sqrt((4/5)^2) = 4/5# #-4/5# is also a square root of #16/25# , but by convention when we say the square root, we tend to mean the positive one. Answer link