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Calculate the solubility of fe(oh)3 in water - Brainly The solubility of Fe(OH)3 (iron(III) hydroxide) in water can be calculated using the solubility product constant (\(K_{sp}\)) for Fe(OH)3. The solubility product constant represents the equilibrium constant for the dissolution of a sparingly soluble compound into its ions in a solution. The solubility product constant expression for Fe(OH)3 is:
Calculate the solubility of Co2 in water at 298 Kelvin under 6 Mar 2020 · the solubility of CO₂ in water at 298 Kelvin under 760 mm Hg is 0.0337 mol/litre - By using Henry's law. P = × x. x = P / = 760 / (1.25 × 10⁶) = 608 × 10⁻⁶ = 6.08 × 10⁻⁴. As mole fraction is related to solubility, hence solubility in terms of mole fraction is 6.08 × 10⁻⁴
11. Calculate the solubility of gaseous oxygen in water at a 18 Apr 2023 · Calculate the solubility of gaseous oxygen in water at a temperature of 293 K when the partial pressure exerted by O₂ is 1 bar. (Given: K₁ for O₂ 34840 bar. mol-¹) H (a) 2.87 x 10-5 mol/L (b) 4x 104 mol/L (c) 2.87 x 10 mol/L (d) 5 x 104 mol/L
Calculate the solubility of agcl in a 0.1m nacl solution 28 Oct 2023 · We can rearrange this equation to solve for the solubility (S): S = Ksp / 0.1. To calculate the solubility of AgCl, you would need the Ksp value for AgCl, which is a constant for this specific compound. Once you have that value, you can use the equation above to find the solubility of AgCl in the 0.1 M NaCl solution.
b- Calculate the solubility of Ca3(PO4)2 (Ksp = 1.3 x 10-32) in … 10 Jan 2024 · Calcium phosphate is a poorly soluble salt compound in water with the following solubility equlibrium: Ca3(PO4)2(s)⇋3Ca2+(aq)+2PO43−(aq)Ksp=1.3×10−32=[Ca2+]3[PO43−]2 0.083 M of calcium nitrate will fully dissociate to provide 0.083 M of calcium cation in solution.
Calculate solubility of a saturated solution of Ag2CrO4 if boiling ... 28 Apr 2024 · To calculate the solubility of a saturated solution of Ag2CrO4, we can use Raoult's law, which states that the vapor pressure of a solution is directly proportional to the mole fraction of the solvent. Given: Boiling point of the saturated solution = 373 K. Vapor pressure of the solvent (Ag2CrO4) = 760 mmHg
21.5 g of sodium chloride dissolves in 60g of water at 25oC. 6 Jun 2016 · Solubility of a Solute = (Wt. of Solute in Sat. Soln. / Wt of Solvent in Sat. Soln.) X 100 (21.5/60) X 100 35.833 g/100 g of Water. As water has density 1g/cc solubility is expressed as 35.833 g/100mL of water
3g of solute is dissolved in 30g of water to form of saturated … So the solubility of the saturated solution mentioned in the question; =Mass of solvent/Mass of water×100 =3/30×100 =10 . So the solubility of the saturated solution mentioned in the question is almost 10. (Answer)
Calculate the solubility of gaseous oxygen in water at a … 8 May 2024 · Therefore solubility of = Hence the solubility of gaseous oxygen in water at 293 K is 0.051 . To learn more about the concept please go through the links. brainly.in/question/10977207. brainly.in/question/9350455. #SPJ1
State Henry's law calculate the solubility of co2 in water at 298 ... 6 Mar 2020 · Solubility of the gas in water. Solution: Let the mole fraction of the gas be . Now, using the formula we have, Mole fraction = Number of moles of solute/ Total number of moles of solution. Let the number of moles of CO₂ be n. But n <<<< 55.5. ∴ We neglect n in the denominator. Now, we have. Hence, Solubility = 0.0338 moles per litre. #SPJ3