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Note: Conversion is based on the latest values and formulas.
How do you solve cos^2 x-sin^2 x=sin x? - Socratic 21 May 2016 · (pi/6),(5pi)/6, (3pi)/2 Replace in the equation cos^2 x by (1 - sin^2 x) --> 1 - sin^2 x - sin^2 x - sin x = 0 -2sin^2 x - sin x + 1 = 0 Solve this quadratic equation in sin x. Since a - b + c …
How do you solve # sin x = -cos^2x-1# in the interval [0, 2pi]? 9 Feb 2016 · x = 3/2 pi You can use the law sin^2 x + cos^2 x = 1 " "<=> " "cos^2 x = 1 - sin^2 x If you plug this into your equation, you have sin x = - (1 - sin^2 x) - 1 sin x = -2 + sin^2 x sin^2 x - …
How does acceleration equal g sin theta? - Answers 20 May 2024 · The equation for normal force is: ( F_{\text{N}} = \text{mg} \cos(\theta) ), where ( F_{\text{N}} ) is the normal force, ( m ) is the mass of the object, ( g ) is the acceleration due to …
What is the general solution of the differential equation - Socratic 16 Feb 2017 · We have: # dy/dx +y = y^2(cosx-sinx) \ \ \ \ \ ..... [1]# This is a First Order Bernoulli differential equation of the form:
How do you find the linearization function of # f(x) = sin(4x) We have: f(x) = sin4x+cosx Here we will obtain an linear approximation (about x=0) using Maclaurin Series from First Principles.
How to express #cot(theta)-csc(theta)# in terms of #sin(theta) 22 Jan 2017 · cot theta-csc theta=cos theta/sin theta-1/sin theta=(cos theta -1)/sin theta=[sqrt(1-sin^2 theta)-1}/sin theta
What is the integral of int sin(x)^3 * cos(x) dx? - Socratic 5 May 2018 · =(sin^4(x))/(4)+C int_ sin^3(x)*cos(x) dx We can use substitution to remove cos(x). So, let's use sin(x) as our source. u=sin(x) Which then means that we will get, (du)/(dx)=cos(x) …
How do you solve # cos^2x = 1 + sinx# on the interval [0,2pi]? 24 Mar 2016 · x= 0, pi, 2pi and (3pi)/2 cos^2 x = 1 - sin^2 x, hence the given equation would become 1-sin^2 x = 1+ sin x Or, " "sin^2 x +sin x=0 Or, " "sin x (sinx +1)=0 This give sin x=0 …
How do you find cos60 using the fundamental identities if 5 Feb 2015 · I would use the double angle formula: cos(2theta)=cos^2(theta)-sin^2(theta) and the fact that: sin^2(theta)+cos^2(theta)=1 giving: cos^2(theta)=1-sin^2(theta) So you get: …
How do you use the product rule to find the derivative of 6 Aug 2014 · The product rule states: d/dx[f(x) * g(x)] = f'(x)*g(x) + f(x)*g'(x) So, if we are trying to find the derivative of y = sqrt(x) * cosx, then we will let f(x) = sqrt(x) and g(x) = cosx. Then, by …