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trigonometry - Prove $\sin^2\theta + \cos^2\theta = 1$ - Mathematics ... 6 Oct 2014 · (Imagine bringing the blue segment down so it lies on top of part of the purple segment - $\sin^2\theta + \cos^2\theta = 1$ (since $\sin^2\theta + \cos^2\theta = 1^2$). Since the radius has …
trigonometry - Is $\cos(x^2)$ the same as $\cos^2(x) In blue, a graph of the function $\color{blue}{\cos^2(x)}$ and in red a graph of the function $\color{red ...
What is $\\sin^2(x) -\\cos^2(y)$? - Mathematics Stack Exchange If one accepts these three identities: $$ \sin^2\theta + \cos^2\theta=1 $$ $$ \sin(x+y)=\sin x \cos y + \cos x \sin y $$ $$ \cos(x+y)=\cos x \cos y - \sin x \sin y $$ Then a large class of other identities …
Prove that $\\cos (A + B)\\cos (A - B) = {\\cos ^2}A - {\\sin ^2}B$ $$\cos (A + B)\cos (A - B) = {\cos ^2}A - {\sin ^2}B$$ I have attempted this question by expanding the left side using the cosine sum and difference formulas and then multiplying, and then simplif...
trigonometry - why is $\cos^2(\theta) + \sin^2(\theta)$ always ... $\cos^2(\theta) + \sin^2(\theta)$ is always equal to $1$ in the mathematical world. This is the Pythagorean Theorem. In the computer world, this is not so because computer arithmetic has …
Solving the inverse of cos^2 - Mathematics Stack Exchange $$ \cos^2 i = {(b/a)^2 − (b/a)^2_{eos} \over 1 − (b/a)^2_{eos}} $$ All I need however is to determine ...
algebra precalculus - Why $\cos^2 (2x) = \frac{1}{2}(1+\cos (4x ... Recall the formula $$\cos(2 \theta) = 2 \cos^2(\theta) - 1$$ This gives us $$\cos^2(\theta) = \dfrac{1+\cos(2 \theta)}{2}$$ Plug in $\theta = 2x$, to get what you want.
functions - What is cos²(x)? - Mathematics Stack Exchange Truthfully, the notation $\cos^2(x)$ should actually mean $\cos(\cos(x)) = (\cos \circ \cos)(x)$, that is, the 2nd iteration or compositional power of $\cos$ with itself, because on an arbitrary space of …
How to integrate $\\cos^2x$? - Mathematics Stack Exchange 15 Jun 2016 · It seems like I am stuck on such a simple problem: How to I find the antiderivative of $\\cos^2x$? I have tried partial integration, it doesn't seem to work (for me). Some help on how to …
trigonometry - Why is $\cos (x)^2$ written as $\cos^2 (x ... 14 Mar 2016 · $\begingroup$ $\cos^2(x)$ may be misinterpreted as $\cos(\cos x)$, which is how you're supposed to interpret the exponent in $\cos^{-1}(x)$. It's confusing, but somehow the two …