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complex numbers - What is $\sqrt {i}$? - Mathematics Stack … -1 is 1 rotated over $\pi$ radians. The square root of a number on the unit circle is the number rotated ...
complex numbers - why is $\sqrt {-1} = i$ and not $\pm i ... 9 Jan 2015 · To get a continuous "branch of square root" it's necessary to remove enough of the plane that "the domain of the square root doesn't encircle the origin". The customary choice is to remove the non-positive reals. (Ironically, this explicitly excludes $-1$ from the domain of the square root.) A common alternative choice is to remove the non ...
Why the square root of any decimal number between 0 and 1 … 24 Jan 2018 · Think about a decimal number between 0 and 1 as a fraction with its numerator GREATER than its denominator. Say you are taking the square root of the number $1/25$. So, you acquire $\sqrt{1/25}$ as the expression which you have to evaluate. This becomes $\sqrt{1}/\sqrt{25}$, or $1/5$. $1/5 > 1/25$.
complex numbers - The negative square root of $-1$ as the value … $\begingroup$ @under-root Well... no, not really. I suggest you re-read my last paragraph. The whole point is that $\sqrt{-1}$ isn't a uniquely defined thing.
What's bad about calling $i$ "the square root of -1"? 28 Mar 2015 · There is a bit more complicated, but more thorough explanation, however, involving complex analysis. The problem lies in trying to take fractional exponents of negative numbers, e.g. $(-1)^{1/2}$.
Approximating square roots using binomial expansion. And one can quickly check that $(x_3)^2=2.000006007\dots$, which is pretty much the square root of $2$. Share.
Is $i$ equal to $\\sqrt{-1}$? - Mathematics Stack Exchange 22 Jul 2017 · Indeed we can extend the definition of the square root to any complex number, setting it as the principal value of $\sqrt z:=e^{1/2\ln z}$ with the same result. However is true that $(-i)^2=-1$. Share
Why is the square root of a negative number impossible? You do not need sci-fi to be convinced because its roots are -1 = -1 x 1 = 1 x -1 or - (1 x 1) = -(-1 x -1). Simple and logical. Finally, the square root calculations of the negative and the positive numbers are the same and their outcomes are differentiated only by plus-minus sign.
How to express $\\sqrt{x} =-1$? - Mathematics Stack Exchange 2 Apr 2015 · In this setting, "$\sqrt{x} = -1$" still has no solution (there is no complex number whose unique square root is $-1$), but we do have $\sqrt{1} = \{-1, 1\}$. But perhaps allowing multi-valued square roots feels like cheating. Unfortunately, matters become problematic if we require a (single-valued) square root function. The essential problem ...
Is the square root of negative 1 equal to i or is it equal to plus or ... 25 Nov 2017 · The answer is that there are two square roots of $-1$. This is no different than with real numbers; for example, there are two square roots of $4$: $2$ and $-2$. The main difference is that the complex numbers don't have a good way to single out one of the two square roots as the "special" one.