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Finding the width function w (y) - Math Help Forum 17 Oct 2016 · Width= (4/9)height. For the second we are told that y= x^2/9. The width is the distance between two x values at a given height (y value). So solve for x: x^2= (9/2)y and then x= \pm\sqrt{(9/2)y}. The "\pm" are the two (left and right) x values and the width is the distance between them, \sqrt{(9/2)y}- (-\sqrt{(9/2)y})= 2\sqrt{(9/2)y}.
Help with Poisson Distribution! - Math Help Forum 10 Mar 2009 · \sigma^2 = 9 \Rightarrow \sigma = \sqrt{9} = 3. Calculate \Pr(3 < X < 15) = \Pr(4 \leq X \leq 14). There's no easy way of doing this by hand - you just have to calculate each probability and then add them all up. You might be able to use the rule of thumb .... It will depend on what accuracy is required.
Triple Integral: Volume problem, Using cylidrical coordinates 8 Dec 2013 · I would like to know why the limits of integration of z is -sqrt(9-r^2) to +sqrt(9-r^2). The radius is at most 3 and at least 1. However if r=3, z=0 which is true when r=3 on the xy-plane but a picture can be used to show that we can find a z=/=0 if r=3. It seems sqrt(9-r^2)=z doesn't give a correct relation between r and z at all for this problem.
surface portion bounded by plane 2x +5y - Math Help Forum 10 Sep 2016 · Find the surface portion bounded by plane 2x +5y + z = 10 that lies in cylinder (x^2) +(y^2) = 9 ... I have skteched out the diagram and my ans is 5sqrt(30) instead of 9sqrt (30) as given by the author ... Anything wrong with my working ?
3 Calculus Questions | Math Help Forum 22 Mar 2007 · 1. A point moves along the curve y = x^2 + 1 so that the x-coordinate is increasing at the constant rate of 3/2 units per second.
Integration: 1/sqrt (9-4x^2) - Math Help Forum 1 Jun 2009 · I am doing some integration drills and I am stuck with this one: \\int \\frac {1}{\\sqrt{9-4x^2}} dx the solution is as follows: u = \\frac {2}{3}x du = \\frac {2}{3 ...
SOLVED What is cos(pi/9)? - Math Help Forum 5 Feb 2013 · I have looked and looked and cannot find an answer in fractional form. I have done multiple trial and errors and have gotten close. The decimal form is (.9396926208), I don't have this on a unit circle and have not found a unit circle that includes this …
Differential Equations (?) - Math Help Forum 13 Jan 2009 · Drag race. Two drivers, Alison and Kevin, are participating in a drag race. Beginning from a standing start, they each proceed with a constant acceleration. Alison covers the last \\frac14 of the distance in 3 seconds, whereas Kevin covers the last \\frac13 of the distance in 4 seconds. Who wins...
forces question - Math Help Forum 20 Feb 2010 · Edit: turns out I get the book answers when I set g = 9.8. For future reference it would be an immense help if you could tell us what the book uses for g as some use 9.8, some 9.81 First of all we need to know what value of g your book uses. I am using g = 9.81 \text {N kg}^{-1} This is a problem with resolving the forces horizontally and ...
Tennis Court | Math Help Forum 3 Nov 2018 · A regulation doubles tennis court has an area of 2808 square feet. If it is 6 feet longer than twice the width, determine the dimension of the court. Let x = width Let = 2x + 6 Let area = A = 2808 ft^2 A = L•W 2808 = (2x + 6)(x) Is this the correct equation set up? If not, why?