=
Note: Conversion is based on the latest values and formulas.
What is the distance between #(2,6)# and #(4,4)#? - Socratic 26 Nov 2015 · 2sqrt(2) Consider these point as forming a triangle. You can then use Pythagoras to solve the length of the hypotenuse (the line between the points. Let the distance be d Let …
How do you simplify #sqrt(27) - sqrt(8) + 2 sqrt(2)#? - Socratic 28 Feb 2016 · It is sqrt(27) - sqrt(8) + 2 sqrt(2)=3*sqrt3-2sqrt2+2sqrt2=3*sqrt3
How do you simplify sqrt8+2sqrt2? - Socratic 4 Jul 2015 · How do you simplify #sqrt8+2sqrt2#? Algebra Radicals and Geometry Connections Addition and Subtraction of Radicals. 1 Answer
Need help - Socratic 12 Oct 2017 · You have base 3.8, hypotenuse 8, so, you can solve for the height: h = sqrt(8^2 - 3.8^2) = 7.0 (rounding to nearest 10th) And the area of each right triangle is therefore 1/2 * 7.0 …
How do you show that sqrt(2-sqrt3)/2=(sqrt6-sqrt2)/4? - Socratic 8 Jun 2017 · First, note that any number in the form a-sqrtb when squared gives a number in the form c-sqrtd. In fact, (a-sqrtb)^2=(a^2+b)-2asqrtb=(a^2+b)-sqrt(4a^2b) The goal here is to …
How do you solve #sqrt(8-x)=x+6# and identify any restrictions? 27 May 2017 · The right side cannot be negative and neither can the argument of the radical. Square both sides. Solve the quadratic. Discard any roots that violate the restrictions. The …
How do I solve #sqrt(-8)(sqrt(-3)-sqrt(5))#? - Socratic 21 Nov 2016 · -2sqrt(6)-(2sqrt10)i or -2sqrt2(sqrt3+isqrt5) "Simplify" is perhaps a better word than "solve", since there's no variable to solve for. First, we rewrite using i notation: sqrt(-8)(sqrt(-3) …
How do you simplify #8/sqrt(8)#? - Socratic 14 May 2015 · Both the numerator and denominator of a fraction can be multiplied by the same real number (not equal to zero), without changing the value of a fraction.
How do you solve #3x^2+2=4x# using the quadratic formula? 8 Feb 2017 · How do you solve #3x^2+2=4x# using the quadratic formula? Algebra Quadratic Equations and Functions Quadratic Formula. 1 Answer
What is the square root of 32 over square root of 8? - Socratic 21 Mar 2018 · See a solution process below: We can rewrite this expression as: sqrt(32)/sqrt(8) => sqrt(8 * 4)/sqrt(8 ...