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Note: Conversion is based on the latest values and formulas.
How do you factor x^{2}-16x-96? - Socratic 3 Apr 2018 · You can use the standard formula. #x_{1,2} = \frac{-b \pm \sqrt(b^2-4ac)}{2a}# if the equation is. #ax^2+bx+c=0# to find its roots.
How do you integrate #int 1/sqrt(e^(2x)+12e^x+32)dx# using 26 Mar 2018 · -sqrt2/8ln|{(16+3e^x)+sqrt(256+96e^x+8e^(2x))}/e^x|+C, or, sqrt2/8[x-ln|{(3e^x+16)+2sqrt2sqrt(e^(2x)+12e^x+32)}|]++C.
How do you solve the equation 2x^2-512=0? - Socratic 28 Apr 2017 · x=+-16 Add 512 to both sides: 2x^2-512+512=0+512 This becomes: 2x^2=512 Divide both sides by 2: (2x^2)/2=512/2 This becomes: x^2=256 Square root both sides: sqrt(x^2)=+-sqrt(256) This becomes: x=+-sqrt(256) Break down 256 into its factors: x=+-sqrt(2*2*2*2*2*2*2*2) Take out pairs of the same number: x=+-(2*2*2*2) This leaves you with: …
Evaluate the following - Socratic 27 Oct 2016 · 256^(5/2) = sqrt(256)^5 =16^5 = 1,048,576 256^(4-3/2) Evaluate means find the value of the expression - you need a number answer. In the exponent there is 4-3/2 This is the same as 4-1 1/2 which is 2 1/2 2 1/2 = 5/2 So we have: 256^(5/2) Recall the law: x^(p/q) = (rootq x)^p The denominator in the index shows a root and the numerator shows a power. 256^(5/2) …
How do you simplify sqrt 256? - Socratic 31 May 2015 · you could start with #15xx15# which equals 225, so you know that is wrong and it's lower than 256. You would than know that the number has to be increased so you could try #17xx17# however that equals 289, which is too high. You would then try #16xx16# which is …
What is the trigonometric form of # (5-2i)(2+3i) - Socratic 6 Jan 2016 · How do you convert complex numbers from standard form to polar form and vice versa?
How do you simplify #sqrt(512k^2)#?? - Socratic 8 Apr 2015 · To simplify this, it is helpful to split up what we have sqrt(512k^2)=sqrt(512)*sqrt(k^2) We can see that the second part becomes just k. Let's look at sqrt(512) and try to find factors that multiply to give 512. Well, let's start by dividing by 2. 512/2=256 256 is a perfect sqaure! It has factors 16*16. However, 512 is not a perfect square.
Between what two consecutive integers do sqrt250 lie? - Socratic 21 Oct 2015 · Between what two consecutive integers do #sqrt250# lie? Algebra Properties of Real Numbers Square Roots and Irrational Numbers. 1 Answer
A cone has a height of 12 cm and its base has a radius of 8 29 Jun 2018 · A = (640/9 + 256/9 sqrt(13)) pi ~~ 173.7 pi " "cm^2 ~~549.6 " "cm^2 Given: cone of h= 12 cm, b = 8 cm. Cut 8cm from the base. Find the surface area of the bottom segment. The new shape is called a conical frustum . It has the surface area formula : A = A_"lateral" + A_"bases" A_"lateral" = pi (r_1 + r_2) sqrt((r_1 - r_2)^2 + h_f^2) A_"bases" = pi((r_1)^2 + …
How do you simplify #\sqrt { \frac { 121} { 256} }#? - Socratic 18 Jun 2017 · We can use this rule for radicals to begin the simplification process: #sqrt(color(red)(a)/color(blue)(b)) = sqrt(color(red)(a))/sqrt(color(blue)(b))#