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Note: Conversion is based on the latest values and formulas.
What is the square root of 164 simplified in radical form? 24 May 2017 · We can think of two numbers that multiply to #164#. If we divide #164# by #4# we get #41#. We can write an expression like this: #sqrt(4)*sqrt(41)=sqrt(164)# If we look closely, …
How do you solve #8x^2-2x-5=0# using the quadratic formula? 12 May 2018 · How do you solve #8x^2-2x-5=0# using the quadratic formula? Algebra Quadratic Equations and Functions Quadratic Formula. 1 Answer
What is the distance between # (–2, 1, 3) # and #(0, 4, –2) - Socratic 16 Feb 2017 · The distance between these two points is #sqrt(38)# or #6.164# rounded to the nearest thousandth Explanation: The formula for calculating the distance between two points is:
What is the square root of 164? - Socratic 11 Mar 2018 · #sqrt(164)=sqrt(4*41)=sqrt(4)*sqrt(41)=2*sqrt(41)~~12.8# Answer link. Related questions
Simplification of Radical Expressions - Algebra - Socratic There are two common ways to simplify radical expressions, depending on the denominator. Using the identities #\sqrt{a}^2=a# and #(a-b)(a+b)=a^2-b^2#, in fact, you can get rid of the …
An object with a mass of 14 kg is acted on by two forces ... - Socratic 5 Aug 2017 · a=0.91 m//s^2 at 51.3^o above the horizontal. We can make use of Newton's second law to solve this problem: vecF_(n e t)=mveca where m is the object's mass and a is the …
What is the distance between #(31,-21)# and #(21,-29)#? - Socratic 16 Dec 2015 · 2sqrt(41) units The distance between two points can be calculated with the formula: d=sqrt((x_2-x_1)^2+(y_2-y_1)^2) where: d=distance (x_1, y_1)=(31, -21) (x_2, y_2 ...
Point A is at (4 ,1 ) and point B is at (-6 ,-7 ). Point A ... - Socratic 16 Feb 2016 · The new point A is at (-1, 4) The changed in distance between points A and B =2sqrt41-sqrt(146)=0.723203 Rotating point A (4, 1) about the origin by (3pi)/2 clockwise will …
How do you solve #6t^4-5t^3+200t+12000 = 175000# - Socratic 11 Jul 2017 · The real solutions are approximately: t ~~ 13.000377 t ~~ -12.6846 Given: p(t) = 6t^4-5t^3+200t+12000 = 175000 This is a slightly strange question, in that there is one answer …
How do you find the zeros, real and imaginary, of - Socratic 13 Dec 2017 · x=3+sqrt(41)i,3-sqrt(41)i Given: y=(x-3)^2+41 Expand (x-3)^2. y=x^2-6x+9+41 Simplify. y=x^2-6x+50 is a quadratic equation in standard form: y=ax^2+bx+c, where: a=1, b= …