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Note: Conversion is based on the latest values and formulas.
How do you evaluate #sin(pi/6) - Socratic 11 Jan 2018 · sin(pi/6) = 1/2 Start with an equilateral triangle of side 2. The interior angle at each vertex must be pi/3 since 6 such angles make up a complete 2pi circle. Then bisect the triangle through a vertex and the middle of the opposite side, dividing it into two right angled triangles. These will have sides of length 2, 1 and sqrt(2^2-1^2) = sqrt(3). The interior angles of each …
How do you use the half angle identify to find the exact value of 27 Feb 2017 · sin (pi/8) = sqrt(2 - sqrt2)/2 Use trig identity: 2sin^2 a = 1 - cos 2a In this case, a = pi/8 and 2a = pi/4 --> cos pi/4 = sqrt2/2 --> 2sin^2 (pi/8) = 1 - sqrt2/2 ...
How do I evaluate sin(pi/3) without using a calculator? 29 Aug 2015 · sin(pi/3) = sqrt(3)/2 Consider the series of diagrams below. The interior angles of a triangle always add up to pi radians An equilateral triangle will have all three angles = pi/3 and all three sides of equal length. If we set the sides of the equilateral triangle to 2 we can avoid fractions when we divide the triangle into 2 halves vertically, By the Pythagorean Theorem, the …
How do you simplify #sin(x+pi)#? - Socratic 31 Jul 2016 · #rArrsin(x+pi)=-sinx# Answer link. Related questions. What are some sum and difference identities examples
What is the average value of a function sin(X) on the interval [0, pi ... 4 Jun 2016 · 2/pi. Average =(int sin x dx) /pi, over the interval [0, pi] The denominator is the length of the interval of integration.t. =[-cos x]/pi, between the limits [0, pi ...
What is the value of cos(pi/4)? - Socratic 13 Apr 2018 · sqrt2/2 As you can see in the table above, cos45^@ or cospi/4 radians is the same thing as sqrt2/2 An alternative way is looking at the unit circle: We know that the cosine of an angle is the x-value of a coordinate. At pi/4, we can see that the x-value is sqrt2/2. Therefore, cos(pi/4) = sqrt2/2 Hope this helps!
How do you simplify #sin(x-pi/2)#? - Socratic 16 Aug 2016 · #sin(x- pi/2)# is just #sinx# translated by #(pi/2,0)# We see that #sinx#: graph{sinx [-4.006, 4.006, -2.003, 2.003]} #therefore sin(x-pi/2) #: graph{sin(x- pi/2) [-4.006, 4.006, -2.003, 2.003]} By observing this new graph, we see that this is just #cosx# reflected in the #x# axis. Hence just: #=> -cosx #
How do you evaluate sin(π/4)? - Socratic 11 Feb 2016 · sqrt(2)/2 In the trigonometric circle pi/4 is the bisectrix between 0 and pi/2, where x=y. By the Pythogoras theorem we know that x^2+y^2=1. If you don't know the trigonometric circle, you can see that if one of the small angles of a rectangle triangle is pi/4, the other will be also pi/4, which implies the catets are equal. So if x=y, you will have x^2+y^2=1 2y^2=1 …
Does sin(pi-x) = sin(x)? - Socratic 15 Apr 2015 · How do you use the sum and difference identities to find the exact value of tan 105 degrees
How do I find the value of sin 5pi / 6? - Socratic 8 Aug 2015 · sin (5pi)/6= 1/2 Sin (5pi)/6= sin (pi- pi/6)= sin pi/6= sin 30 = 1/2 Another way to think about it is to draw the angle in a Unit circle and create the "new" triangle in Quadrant II. Drop a perpendicular to the x-axis and you will have the correct triangle to use. From this triangle, you need the opposite leg length, which is 1/2. Since the hypotenuse is equal to 1 in the Unit circle, …