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Note: Conversion is based on the latest values and formulas.
How do you graph #y = 2 - 4 cos (x - pi/6)#? - Socratic 7 Oct 2015 · Start with the parent function cos(x) then apply the translations. This is a cosine function with the following translations: 1) Amplitude is 4, but the negative sign flips the graph over the horizontal axis . 2) The -pi/6 will shift the entire graph to the right pi/6 units 3) Finally, the value 2 shifts the entire graph upward 2 units. Here is the graph: Hope that helped
What is the average rate of change of the function - Socratic 22 Mar 2018 · The average rate of change of a function on the interval #[a,b]#, is given by: #(f(b)-f(a))/(b-a)# #f(x)=sinx# For #[0,pi]#
How do you find the critical points to graph y= 2 sin (-2x+pi) +1 ... 24 Jun 2018 · As below Standard form of sine function is y = A sin (Bx - C) + D Given y = 2 sin(-2x + pi) + 1 A = 2, B = -2, C = -pi, D = 1 Amplitude = |A| = 2 "Period " = (2pi ...
Use the half-angle formulas to determine the exact values of sine ... 25 May 2018 · Use the half-angle formulas to determine the exact values of sine, cosine, and tangent of the angle.? 11pi/12
Find the value of #cos(sin^-1(sqrt3/2))#? - Socratic 18 Dec 2016 · cos(sin^-1(sqrt3/2))=1/2 sin^-1x means an angle whose sine ratio is x. If angle is A, then it means sinA=x. Further, although there may be number of values of A, for whom sine is x - as all trigonometric ratios have a cycle of 2pi radians, the range for inverse ratios is limited. While for sine, tangent, cosecant and cotangent range is [-pi/2.pi/2], range for cosine and secant ratios, it is …
How do you graph #y=-2+cos(1/2(x-pi))#? - Socratic 22 Mar 2017 · Graph the cos(x) graph with a few transformations, streches, and shrinks. This is essentially the cosine graph with a few changes. First, because the expression with x is (x-pi) we must first shift the graph over to the right by pi units. Next, because that expression is multiplied by half, we will double the length of the period. This is because it takes twice the magnitude of x to …
How do you use the sum and difference identities to find the exact ... 17 Jul 2015 · Find 3 trig functions of ((7pi)/12) Call sin ((7pi)/12) = sin t -> cos 2t = cos ((14pi)/12) On the trig unit circle. cos ((14pi)/12) = cos (pi/6 + pi) = - cos (pi/6 ...
A triangle has vertices A, B, and C. Vertex A has an angle of pi/8 ... 23 Jul 2016 · ~~6.97 The third angle of the triangle is /_C = pi -pi/4-pi/8={5 pi}/8 Sine law gives us a/{sin (pi/8)} = b/{sin(pi/4)}=c/{sin({5 pi}/8)} = k ( "say") The area is given by A = 1/2 b c sin/_A = 1/2 k^2 sin/_A sin/_B sin/_C = 1/2 k^2 sin(pi/8) sin(pi/4)sin({5pi}/8) = 1/2 k^2 sin(pi/8) sin(pi/4) cos(pi/4) = 1/4 k^2 sin^2(pi/4) = 1/8 k^2 and thus k^2 = 8 xx 18 = 144 or k=12. Now, the radius of the ...
How do you find the period, amplitude and sketch y=-4sin (2/3x-pi/3 ... As below. y = -4 sin(2/3 x - pi/3) Standard form of the sine function is y = A sin (Bx - C) + D A = -4, B = 2/3, C = pi/3, D = 0 Amplitude = |A| = |-4| = 4 Period ...
A circle has a chord that goes from ( 3 pi)/4 to (5 pi) / 4 ... - Socratic 24 Dec 2017 · Obtain the radius r = 9 from the area, visualize the problem if needed, and find that the chord must be double the sine of the angle inside the triangle times the radius, to get L_"chord" = 9 sqrt(2). First, let's obtain the radius from the area: A = pi r^2 = 81 pi Here, pi cancels out: r^2 = 81 And taking the square root gets us: r = 9. Here's what the circle looks like: Just like any other ...