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Note: Conversion is based on the latest values and formulas.
How do you evaluate #Sin(π/3)*tan(π/6)#? - Socratic 27 Nov 2016 · 1/2 sin(pi/3)xxtan(pi/6) " " =sqrt3/2xxsqrt3/3 " " =sqrt(3^2)/(2xx3) " " =3/(2xx3) " " =1/2
How do you use the sum and difference identity to evaluate 20 Aug 2016 · sqrt(2 + sqrt3)/2 Trig unit circle --> sin ((7pi)/12) = sin (pi/12 + pi/2) = cos (pi/12) Find cos (pi/12) by using the trig identity: cos 2a = 2cos^2 a - 1 cos ((2pi ...
How do you use the half-angle identity to find the exact value of … 19 Jul 2015 · Find sin (-pi/12) Answer: - 0.259 Call sin (-pi/12) = sin t -> cos 2t = cos (- pi/6) = cos (pi/6) = sqrt3/2 Use trig identity: cos 2t = sqrt3/2 = 1 - 2sin^2 t 2sin^2 t = (2 - sqrt3)/2 sin^2 t = (2 -sqrt3)/4 sin t = sin (-pi/12) = +- sqrt(2 - sqrt3)/2 = +- 0.259. Only the negative answer is accepted: - …
How do you evaluate sin(11π/6)? - Socratic 17 Mar 2018 · To find the value of #sin ((11pi)/6)#. #sin ((11pi)/6) = sin (((11pi)/6) - 2pi) # # => sin -(pi/6) = - sin (pi/6)# as sin in IV quadrant is negative.
How do you solve #sin(pi/5-pi/2)#? - Socratic 11 May 2018 · #sin(pi/5 - pi/2) = sin(36^circ - 90^circ) = cos(90 - (36^circ - 90^circ)) = cos(180^circ-36^circ) = cos 144^circ # Strap in, this is where it gets interesting. First we note #cos(3 theta)=cos(2 theta)# has solutions #3 theta = pm 2 theta + 360^circ k,# integer #k# , or just using the subsuming minus sign,
How do you simplify Sin pi/12 times Cos pi/12? - Socratic 26 Mar 2016 · Apply the trig identity: sin 2a = 2sin a.cos a #sin (pi/12).cos (pi/12) = (1/2)sin (pi/6)#
How do you evaluate the inverse sin of the sin of pi over 9? 8 Apr 2018 · #arcsin(sin(pi/9))=pi/9# The above makes sense if you think about what the inverse of a function is. If we have an angle #x# and we put this through the function: #f(x)=sinx# we get a ratio returned. When we put the ratio in the inverse function . …
How do you find the exact values sin (pi/4) using the ... - Socratic 4 Aug 2015 · How do you find the exact values #sin (pi/4)# using the special triangles?
Find the exact value of sin (pi/12) , cos (11pi/12) , and ... - Socratic 19 Aug 2015 · #sin (pi/12)# #=sin(pi/3 - pi/4)# #=sin(pi/3)cos(pi/4)-cos(pi/3)sin(pi/4)# #=(sqrt(3)/2)(1/sqrt(2))-(1/2)(1/sqrt(2))#
How do you find sin(-pi/2)? - Socratic 4 May 2018 · What is the value of #sin -45^@#? How do you find the trigonometric functions of values that are greater than #360^@#? How do you use the reference angles to find #sin210cos330-tan 135#?