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A triangle has vertices A, B, and C. Vertex A has an angle of pi/2 ... 18 Jun 2017 · A triangle has vertices A, B, and C. Vertex A has an angle of π 2, vertex B has an angle of π 4, and the triangle's area is 25. What is the area of the triangle's incircle?
How do you find the exact functional value sin (arcsin3/5 - Socratic 24 Sep 2015 · How do you find the exact functional value sin (arcsin3/5 + arccos3/5) using the cosine sum or difference identity?
Question #3534f - Socratic RHS=sin (A/2) (b+c) =sin (A/2) (2RsinB+2RsinC) =2Rsin (A/2) (sinB+sinC) =2Rsin (A/2)sin ( (B+C)/2)cos ( (B-C)/2) =2Rsin (A/2)sin (pi/2-A/2)cos (B/2-pi/2+A/2+B/2) =2Rsin (A/2)cos …
How do you solve for all solutions of x in sin2x-1=0? | Socratic 15 Feb 2015 · (This is probably an attempt to try to trick you into using a double angle formula). Let theta = 2x So the problem becomes: sin (theta) - 1 = 0 or sin (theta) = 1 Within the range …
Can anyone help me to solve sinx=cos (x+ (π/6)) for -π<x<π? 21 Jul 2017 · Explanation: As #cosx=sin (pi/2-x)# #cos (x+pi/6)=sin (pi/2-x-pi/6)=sin (pi/3-x)# As such our equation is #sin (pi/3-x)=sinx# hence #pi/3-x=x# i.e. #2x=pi/3# and #x=pi/6# …
What does csc pi/2 equal? - Socratic 7 Sep 2015 · What does csc pi/2 equal? Trigonometry Right Triangles Trigonometric Functions of Any Angle
Find the exact value of the six trigonometric functions for x if sin ... 17 Nov 2017 · Find the exact value of the six trigonometric functions for x if sin(π 2 − x) = − 3 5 What are the exact values? π <x <3π 2 I understand sin= opp/hyp and that since sin is …
2sin^(2)x-sinx=1 Find the general form and all solutions in the ... 2sin^ (2)x-sinx=1 Find the general form and all solutions in the interval [0,2pi) ?
How do you find the critical points to graph y= 2 sin (-2x+pi) +1 ... 24 Jun 2018 · How do you find the critical points to graph y = 2 sin(− 2x + π) + 1? Trigonometry Graphing Trigonometric Functions Translating Sine and Cosine Functions
Question #ba17d - Socratic 15 Jun 2016 · lim_ (x->pi/2) (2x-sin (2x))/x^2=4/pi lim_ (x->0) (2x-sin (2x))/x^2=0 As the function is continuous at every point except x=0, we can solve the first one by direct ...