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"Let $\\epsilon > 0$ be given ...." is $\\epsilon < 1$ ok? 21 Sep 2016 · $\epsilon$ is arbitrary in definition. For every $\epsilon>0$ there must be a $\delta$ so that the definition holds - it means that definition must be satisfied for every positive …
real analysis - What is the value of $\delta $ if $\epsilon=0.01 ... $\begingroup$ One can choose any value of $\delta<0.004$ and guarantee that the ration of interest in bounded in absolute value by $0.01$. $\endgroup$ – Mark Viola Commented Feb …
statistics - expected value for $(f(X) + \epsilon - \hat{f}(X))^2 ... 16 May 2019 · Stack Exchange Network. Stack Exchange network consists of 183 Q&A communities including Stack Overflow, the largest, most trusted online community for …
How is $\epsilon_0$ countable? - Mathematics Stack Exchange Therefore we have $\aleph_1$ many distinct ordinals below $\epsilon_{\omega_1}$, therefore it is not a countable ordinal anymore. In fact $\epsilon_{\omega_1}$ is the limit of all those …
proof explanation - What does $\epsilon > 0$ is arbitrary mean ... 30 Oct 2017 · $\operatorname{diam}(\bar{E}) \leq \operatorname{diam}(E)+ε.$ Since $\epsilon > 0$ is arbitrary, $\operatorname{diam}(\bar{E}) \leq \operatorname{diam}(E)$. I'm not sure how …
Is an algorithm known for ordering natural numbers in the I have read that there are countable ordinals which can not be reached using algebraic operations and limits starting from $1$, but $\\epsilon_0 = \\omega \\uparrow\\uparrow \\omega$ is …
Absolute value zero is always less than a positive number 16 Jan 2020 · What you must show is that $$(\forall \epsilon > 0: |a|<\epsilon) \rightarrow (a=0).$$ The scope of the quantifier is very important here. To actually solve the second part, I suggest …
What does the letter epsilon signify in mathematics? [closed] $\begingroup$ Historically, the symbol $\in$ is derived from $\epsilon$, thus it is not impossible to confuse both symbols. Also, not as ubiquitous as its primary usage, this Greek symbol …
notation - How to denote a very small number $\epsilon 3 Nov 2016 · When adding a "small" positive number $\epsilon$ to some quantity, one should/might have some criterion in mind that $\epsilon$ should be "small enough" so that …
If $\\epsilon$ is arbitrary, why is $\\epsilon$ zero here? 9 Oct 2020 · If Epsilon is zero as in the last line of the answer provided, then wouldn't the limit definition fail? So Epislon has to be larger than zero? Please see the last line of the proof, …