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Note: Conversion is based on the latest values and formulas.
Eigenstates of the creation operator - Physics Stack Exchange 4 Dec 2018 · In view of the above, I would say that the naive argument that is often found: "a coherent state resembles a classical state because if you annihilate excitations it does not change", is rather wrong. In fact the converse should also be true, which is only the case if $\vert\alpha\rangle$ is eigenstate of $\hat{a}^\dagger$ as well.
quantum mechanics - Instantaneous eigenstate and time dependent ... 31 Mar 2022 · Instantaneous eigenstate $\psi(t)$ is defined as $\hat H(t)\psi(t)=E(t)\psi(t)\tag{1}$ But in the lecture notes of Quantum Physics III MIT (in the section of adiabatic approximation), it is written that $\psi(t)$ may not be the solution of time dependent Schrödinger equation.
What are the Eigenstates and Eigenvalues? [closed] 10 Jun 2019 · $\begingroup$ Eigenstate is quantum state which has definite value for some physical property (for example "particle is definitely at x=0"), eigenvalue (so in that example, x=0 is a position eigenvalue). This concept is meaningful in quantum mechanics because the quantum state does not always give a single definitive value for a physical ...
What is an Eigenstate? Simple Explanation - Physics Forums 24 Mar 2020 · Given an operator, (for example, the Hamiltonian, or the Schrödinger Equation) an eigenstate is a (non-zero) state that, when applied on the operator, results of itself multiplied by some constant factor (that is known as the eigenvalue).
quantum mechanics - How do you calculate the spin eigenstates in … 14 Apr 2023 · I was wondering how does one go about solving for the spin (1/2) eigenstates in an arbitrary direction? Let me specify my question.
Simultaneous eigenstates of Hamiltonian and momentum operator 12 Jun 2019 · Then $\{\vert n\ell m\rangle\}$ are simultaneous eigenvectors of $\hat H$ and $\hat L^2$ but a combination of these containing different $\ell$ s will not be a simultaneous eigenstate of both since different $\ell$ states have different eigenvalues of $\hat L^2$.
What conditions must eigenvalues satisfy for degenerate states? 31 May 2017 · 3)Find another such commuting observable and keep on doing so till every eigenstate can be labeled uniquely. This is why we say that in QM, the state of any system is specified by the Complete set of Commuting Observable's. The above mentioned thought process was carried out to show the role of degeneracy and what it exactly is, in a general sense.
Eigenfunctions v.s. eigenstates - Physics Stack Exchange Maybe in principle, not really in practice. Most people talking casually will use the interchangeably. If you want a rule that makes sense though, "states" are what we call the objects that live in a hilbert space (we also call them vectors, thus eigenvectors!) so the generic, "coordinate-independent" ket should be the eigenstate.
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What is an energy eigenstate exactly? - Physics Stack Exchange "Energy eigenstate" just means "eigenstate of the Hamiltonian." So there is no such thing as an energy eigenstate without a Hamiltonian, just as there is no such thing as an eigenvector without a matrix. $\endgroup$ –