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Derivative of Sin X - Formula, Derivation and Examples - BYJU'S (i.e) The derivative of sin x is cos x. In this article, we are going to learn what is the derivative of sin x, how to derive the derivative of sin x with a complete explanation and many solved …
How do you differentiate #sin^2(2x)#? - Socratic 23 Jul 2016 · How do you compute the 200th derivative of #f(x)=sin(2x)#? How do you find the derivative of #sin(x^2+1)#? See all questions in Differentiating sin(x) from First Principles
What is the derivative of #sin(sin(x))#? - Socratic 27 Sep 2015 · d/dxsin(sinx)=cos(sinx)*cosx The rule says that the derivative of the sine of a function is the cosine of the function multiplied by the derivative of the function, therefore …
How do you differentiate Sin ^ 3 x? | Socratic 13 Jul 2016 · In order to differentiate #sin^3(x)#, we need to use a chain rule, which tells us that. #d/dx[f(g(x))] = f'(g(x))*g'(x)# Letting #y = sin^(3)(x)#, then. #dy/dx = 3sin^2(x) *cos x# In this …
Differentiating sin(x) from First Principles - Calculus - Socratic The derivative of \\sin(x) can be found from first principles. Doing this requires using the angle sum formula for sin, as well as trigonometric limits.
How do you find the derivative of #sin^-1(x)#? - Socratic 12 Apr 2016 · To find derivative of #sin^(-1)x#, we use the concept of function of a function. Let #y=sin^(-1)x#, then #x=siny# Taking derivatives of both sides, we get #1=cosy.dy/dx# or …
What is the derivative of #-sin(x)#? - Socratic 23 Dec 2014 · The previous answer contains mistakes. Here is the correct derivation. First of all, the minus sign in front of a function f(x)=-sin(x), when taking a derivative, would change the …
How do I differentiate sin^2(x)? - MyTutor (x) sin(x). We use the substitution u = sin(x). This is our initial function, and we can see now that using this new notation, y = sin2(x) is simply y = u2. To find: We need to apply the chain rule. …
What is the derivative of #sin^-1(x)#? - Socratic 15 Apr 2016 · 1/sqrt(1-x^2) Let y=sin^-1x, so siny=x and -pi/2 <= y <= pi/2 (by the definition of inverse sine). Now differentiate implicitly: cosy dy/dx = 1, so dy/dx = 1/cosy.
What is the derivative of #sin^2(x)#? - Socratic 8 Sep 2014 · Answer 2sin(x)cos(x) Explanation You would use the chain rule to solve this. To do that, you'll have to determine what the "outer" function is and what the "inner" function …