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Note: Conversion is based on the latest values and formulas.
Differentiate $\\cosh^2(2x)$ - Mathematics Stack Exchange 8 Apr 2018 · But when I attempted the question, I tried to convert $\cosh^2(2x)$ into $\frac{\cosh(4x)+1}2$, using the identity $\cosh(2x)=2\cosh^2(x)-1$. After the conversion, the answer I get differentiating this will be $2\sinh(4x)$ which is a different answer?
Deducing that $\cosh$ and $\sinh$ are entire and calculating the ... 13 Apr 2017 · Complex derivative of $\cos(x) \cosh(y)-i \sin(x) \sinh(y)$ 0. finding a function holomorphic on $\mathbb ...
Differentiate $\\cosh(x^2)$ - Mathematics Stack Exchange What's wrong with my differentiation (help finding a derivative)? 1 Derivative of a function with hyperbolic cosine and exponent $\frac{e^{4x}}{x^3 \cosh (2x)}$
What is the derivative of $y= (\cosh\,x)^x$ - Mathematics Stack … 25 Nov 2016 · $y=(\cosh\,x)^x$ You need to find derivative of $y\;$with respect to $x.$ So solve it using log-$ln\,y = x\,\ln\,\cosh\,x$
Why ${\\rm arcosh}(\\cosh x) =x - Mathematics Stack Exchange Stack Exchange Network. Stack Exchange network consists of 183 Q&A communities including Stack Overflow, the largest, most trusted online community for developers to learn, share their knowledge, and build their careers.
Deriving $\\cosh^{-1}{x}=\\ln\\left(x+\\sqrt{x^2-1}\\right)$ Stack Exchange Network. Stack Exchange network consists of 183 Q&A communities including Stack Overflow, the largest, most trusted online community for developers to learn, share their knowledge, and build their careers.
Differentiate $y=\\cosh^{3} 4x$. - Mathematics Stack Exchange The answer for the first question : Because $\cosh^2(x)=\cosh(x)\cosh(x).$ The answer for the second question : No, it's not true. The answer is what I wrote above.
partial derivative - Why are $\cosh$ and $\sinh$ used in solving … 25 May 2017 · Tour Start here for a quick overview of the site
calculus - Inverse of cosh(x) - Mathematics Stack Exchange Stack Exchange Network. Stack Exchange network consists of 183 Q&A communities including Stack Overflow, the largest, most trusted online community for developers to learn, share their knowledge, and build their careers.
hyperbolic functions - Derivatives of $\sinh x$ and $\cosh x ... $\cosh x = \cos ix$ $\sinh x = i \sin ix$ which, IMO, conveys intuition that any fact about the circular functions can be translated into an analogous fact about hyperbolic functions. e.g. I know that there is a double-angle formula for $\cos$. Therefore, there should be a similar double-angle formula for $\cosh$.