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Note: Conversion is based on the latest values and formulas.
How do you evaluate sqrt(b^2-4ac) for a=2, b=-5, c=2? - Socratic +-3 sqrt(b^2-4ac)" "->" "sqrt((-5)^2-4(2)(2)) sqrt(+25-16)=sqrt(9)=+-3. To solve this you must substitute: #color(red)(2)# for #color(red)(a)# in the expression.
How do I know how many solutions a quadratic equation has? As I said, we cannot take the square root of a negative number, so if b 2 - 4ac is negative, we have an error, and no solutions. This is the key to knowing how many solutions we have: If b 2 - 4ac is positive (>0) then we have 2 solutions. If b 2 - 4ac is 0 then we have only one solution as the formula is reduced to x = [-b ± 0]/2a.
What term is b^2-4ac? + Example - Socratic 26 Mar 2018 · It is not a term; it is a part of the quadratic formula. It is called the discriminant. Quadratic formula: (-b+-sqrt(b^2-4ac))/(2a) The quadratic equation is used to solve quadratic equations (in the format ax^2+bx+c such as x^2-4x+6. The discriminant is used to determine how many different solutions and what type of solutions a quadratic equation will have. For …
What is the improved quadratic formula to solve quadratic … 1 Jan 2018 · There is only one quadratic formula, that is x=(-b+-sqrt(b^2-4ac))/(2a). For a general solution of x in ax^2+bx+c=0, we can derive the quadratic formula x=(-b+-sqrt(b^2-4ac))/(2a). ax^2+bx+c=0 ax^2+bx=-c 4a^2x^2+4abx=-4ac 4a^2x^2+4abx+b^2=b^2-4ac Now, you can factorize. (2ax+b)^2=b^2-4ac 2ax+b=+-sqrt(b^2-4ac) 2ax=-b+-sqrt(b^2-4ac) :.x=(-b+-sqrt(b^2 …
How do you derive the quadratic formula? - MyTutor (x + b/2a)^2 - b^2/4a^2 + c/a = 0 Rearranging and putting the two terms outside the bracket above a common denominator: (x+b/2a)^2 = (b^2 - 4ac)/4a^2 Taking the square root of both sides: x + b/2a = +-sqrt(b^2 - 4ac)/2a (where +- indicates we can take either the positive or negative solution) Finally, rearranging for x: x = (-b +- sqrt(b^2 ...
What is the quadratic formula? | Socratic 26 Mar 2018 · x=(-b+-sqrt(b^2-4ac))/(2a) Negative b plus minus the square root of b squared minus 4*a*c over 2*a. To plug something into the quadratic formula the equation needs to be in standard form (ax^2 + bx^2 +c ). hope this helps!
Solutions Using the Discriminant - Algebra - Socratic #Delta=b^2-4ac=1+4*2=9>0#, giving #2# real distinct solutions. The discriminant can also come in handy when attempting to factorize quadratics. If #Delta# is a square number, then the quadratic will factorize, (since the square root in the quadratic formula will be rational).
Why does the discriminant b^2-4ac determine the number of The rule for the discriminant: if b^2-4ac>0 then the quadratic has two roots if b^2-4ac=0 then the quadratic has one root if b^2-4ac<0 then the quadratic has no rootsRecall that the formula for solving the quadratic equation ax^2+bx+c=0 is x=(-b+(b^2-4ac)^0.5)/2a.
4ac = 0 can someone briefly explain thanks - The Student Room 11 Jun 2024 · If you think about the quadratic formula for the solutions of ax^2 + bx+c=0 you'll see that the roots are (i) repeated/equal if b^2-4ac =0 (ii) distinct if b^2-4ac >0 (iii) complex and conjugate (or there are no real roots) if b^2-4ac <0, because here is a negative number you can't take the square root of (unless you have knowledge of complex ...
Discriminants and determining the number of real roots of a The discriminant, D = b 2 - 4ac Note: This is the expression inside the square root of the quadratic formula There are three cases for the discriminant; Case 1: b 2 - 4ac > 0 If the discriminant is greater than zero, this means that the quadratic equation has two real, distinct (different) roots. Example x 2 - 5x + 2 = 0. a = 1, b = -5, c = 2