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How do you factor -4x^2+5x-12? - Socratic 23 Jun 2017 · can't be factored. D = b^2 - 4ac = 25 - 192 = - 167 < 0 This trinomial can't be factored because D < 0 and D isn't a perfect square.
How do you factor 3x^2 + 5x - 12? | Socratic 30 May 2015 · A=3, B=5, C=12 Since the sign on the constant term is -, look for a pair of factors of AC=36 whose difference is B=5 The pair 4, 9 works. Now use that pair to split the middle term, …
How do you solve 5(x-4)=5x+12? - Socratic 15 Apr 2018 · No solution for the given equation. 5 (x-4) = 5x + 12 5x - 20 = 5x + 12, " removing bracket on L H S" 5x - 5x = 12 + 20, " rearranging like terms together" cancel(5x) - cancel(5x) …
How do you integrate int (5x+12)/(x^2+5x+6) using partial 7 Feb 2016 · ln(x+3)+ln(x+2) +C To begin we must take: (5x+12)/(x^2+5x+6) and decompose it into its partial fractions. First factorise the denominator and then split the fraction up as follows: …
How do you solve 4x - 24= - 5x + 12? - Socratic 22 Jun 2018 · #"add "5x" to both sides"# #4x+5x-24=12# #"add 24 to both sides"# #9x=12+24=36# #"divide both sides by 9"# #x=36/9=4# #color(blue)"As a check"# Substitute …
How do you solve -14 + 5x = -12? - Socratic 24 Dec 2015 · How do you solve #-14 + 5x = -12#? Algebra. 1 Answer Vikki Dec 24, 2015 #x = 2/5# Explanation: The goal of ...
How do you factor 3x^2 - 5x - 12? - Socratic 4 Aug 2017 · #3x^2 -5x -12# is a quadratic trinomial. Find factors of #3 and 12# whose products differ by #5# #" "3 ...
Let f(x) = 5x + 12 how do you find #f^-1(x)#? - Socratic 28 Aug 2016 · See explanation for the answer f^(-1)(x) = ( x - 12 )/5. Disambiguation: If y = f(x), then x = f^(-1)y. If the function is bijective for x in (a, b), then there is 1-1 correspondence …
How do you factor #2x^2-5x-12 - Socratic 5 Aug 2015 · =color(green)((2x+3)(x-4) 2x^2−5x−12 We can Split the Middle Term of this expression to factorise it. In this technique, if we have to factorise an expression like ax^2 + bx …
How do you solve |12- 5x | < 22? - Socratic 27 Sep 2016 · #-5x+12<22# and #-5x+12> -22# We can subtract #12# from both sides in both inequalities to get #-5x<10# and #-5x> -34# Next, we can divide both sides by #-5#. Recall the …