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write showing all working the following algebraic expression as a ... Find the coordinates of the minimum point of the function y=(x-5)(2x-2) Answered by Phoebe C. Work out 7/(2x^2) + 4/3x as a single fraction in its simplest form.
Factorise and solve x^2 + 3x - 4 = 0 | MyTutor To factorise this equation, we must find two numbers that add together to make 3 and multiply to make -4. These numbers must be -3 and -1. We would then rewrite the equation as (x-3)(x-1)=0. To solve this equation, we need to make either (x-3)=0 or (x-1)=0. This means that there are two solutions to this question. x-3=0 and x-1=0
Solve x^2 - 6x + 8 < 0 | MyTutor The x^2 - 6x + 8 equation is often written as equal to y. This is called a Quadratic Equation. ( x^2 - 6x + 8 = y). Our next step is to set this quadratic equation to 0 (i.e. y=0). We then factorise the equation giving (x - 2)(x - 4) = 0. This gives us solutions of x = 2 and x = 4. We have solved for the x values where y = 0 . Graphically, that ...
Solve x^2 = 4 (x – 3)^2 - 3)^2 | MyTutor x 2 =4(x-3) 2. To do this we first expand the brackets. Remeber anything squared means times it by itself (x-3) 2 =(x-3)(x-3) =x 2-6x+9. This makes the equation look like this x 2 =4(x 2-6x+9) We know times the brakcet out by the 4 to give us x 2 =4x 2-24x+36. To solve this question we need to find x, to this we can see that we can minus x 2 ...
From factorising a^2-b^2 hence or otherwise simplify fully (x^2 First the student should recognise that a 2-b 2 = (a-b)(a+b). Using this to solve (x 2 +4) 2-(x 2-2) 2 - Where a = (x 2 +4) and b = (x 2-2). Therefore substituting a and b into (a-b)(a+b)...(x 2 +4+x 2-2)(x 2 +4-x 2 +2) and simplifying...(2x 2 +2)(6). Expanding out the brackets gives: 12x 2 +12. Factorising out the 12 gives you 12(x 2 +1). The ...
Integrate 4/x^2 - MyTutor First of all, I would ask the tutee if they were familiar with the law of integration. i.e. that you increase the power of the variable (x) by 1, then divide by the new power, and if not then I would clarify this with them.Then, we should manipulate the fraction into a format that we know how to integrate more easily.We know that we can rewrite ...
Find the equation of the tangent to the curve y=x^3 + 4x^2 - 2x - 3 ... Substituting in x=-4, dy/dx = 3(-4) 2 +8(-4)-2, so dy/dx= 14. This means that a=14. We now know the gradient of the tangent (14) and a point which the tangent passes through (-4,5). Using the formula for a point on a straight line with coordinates (c,d) and gradient m, (y-d)/(x-c) = m. So (y-5) / (x-(-4))= 14. Multiplying both sides of the ...
Given that y = 2^x, express 4^x in terms of y. - MyTutor Find the gradient of the function f(x,y)=x^3 + y^3 -3xy at the point (2,1), given that f(2,1) = 6. Answered by Daniel D. Integrate (12x^5 - 8x^3 + 3)dx giving the terms of the answer in the simplest terms
How do you change the subject of the formula? - MyTutor At the moment on the right hand side we have x - 4. So, because we want x on its own what we can do is add 4 to this side. However, we must then add 4 to the left hand side to balance the equation (remember what we do to one side when changing the subject of the formula WE MUST DO TO THE OTHER SIDE). This then gives us the following: 4y + 2 +4 ...
Given that y={(x^2+4)(x−3)}/2x, find dy/dx in its simplest form. Looking at the problem to start we can see that this is an algebraic division problemThere are three common methods you will come across for finding dy/dx for algebraic problems: The Chain Rule, The Product Rule and The Quotient Rule.This case will be solved using the Quotient Rule The Quotient Rule Formula is as follows: dy/dx= [v.(du/dx) + u(dv/dx)] / v^2Solving the …