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View question - what is 2 to the negative 4th power? - Web 2.0 ... 2 Oct 2014 · 2 ^ -4 = 1 / 2^4 = 1 / 16 = 0.0625 If you have a number to a negative exponent, rewrite that number in the denumerator with a positive exponent. geno3141 Oct 2, 2014
SOLUTION: simplify. x to the 4th power minus y to the 4th power (1) (x^4 - y^4), which is the difference of two perfect squares, so we can factor it into the product of the sum and difference or (2) (x^2 + y^2)*(x^2 - y^2) The first factor cannot be factored unless you use imaginary numbers. The second factor, however, is again the difference of two perfect squares and will factor to give your final answer
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What watt of a bulb can a 9 volt use? - Answers 14 Sep 2023 · Given that power is 4.5 W and current is 0.5 A, you can rearrange the formula to solve for voltage: V = P / I. Plugging in the values, V = 4.5 W / 0.5 A, which equals 9 volts.
4 to the second power is shown as 4^2 - Algebra Homework Help Question 410477: What is 4 to the 2nd power times 2 to the 2nd power equal. Can u please show me the whole operation. Can u please show me the whole operation. Answer by Theo(13342) ( Show Source ):
SOLUTION: What is 9 to the negative fourth power - Algebra … You can put this solution on YOUR website! What is 9 to the negative fourth power-----9^-4 = 1/9^4 = 0.000152416...
View question - 81 to the power of a 1/4 - Web 2.0 scientific … 22 Sep 2014 · 81 to the power of a 1/4. ... The square root of 81 is 9 and the square root of 9 is 3, so 81 1/4 = 3 (or -3)
SOLUTION: How do you simplify the square root of 81x to the … the 3rd square root of 8g to the 6th power? (8g^6)^(1/3) = 2g^2 ===== Cheers, Stan H. ...
SOLUTION: How to you work 16 to the 3/4 power - Algebra … You can put this solution on YOUR website! 16 to the 3/4-----16^(3/4)---The "3" means raise to the 3rd power.
For n=0,1,2,3,4 determine the pattern of the powers of n mod 5: The lengths of the cycles of the remainders are 1, or 2, or 4; 8 and 16 are both multiples of all of those. So both n^8 mod 5 and n^16 mod 5 will be the last number in the pattern for each value of n.